A gardening pipe having an internal radius ' $R$ ' is connected to a water sprinkler having ' $n$ ' holes…

A gardening pipe having an internal radius ' $R$ ' is connected to a water sprinkler having ' $n$ ' holes each of radius ' $r$ '. The water in the pipe has a speed ' $v$ '. The speed of water leaving the sprinkler is
  1. $\left(\frac{\mathrm{R}^2}{\mathrm{r}^2}\right) \mathrm{nV}$
  2. $\frac{R^2 v}{n r^2}$
  3. $\left(\frac{\mathrm{nr}^2}{\mathrm{R}^2}\right) \mathrm{V}$
  4. $\left(\frac{n R^2}{r^2}\right) V$

Solution

Using the equation of continuity, we have $\mathrm{A}_1 \mathrm{v}=\mathrm{A}_2 \mathrm{v}^{\prime}$ where $v$ is speed of water in the pipe and $v^{\prime}$ is the speed of water leaving the pipe. Area of the pipe $=\pi \mathrm{R}^2$ Area of each hole in the sprinkler $=\pi r^2$ $\therefore \quad$ Total area of the holes in the sprinkler $=n \pi r^2$ $\pi R^2 v=n \pi r^2 v^{\prime}$ ...from (i) $\therefore \quad \mathrm{v}^{\prime}=\frac{\mathrm{R}^2 \mathrm{v}}{\mathrm{nr}^2}$

Asked in: MHT CET 2024 (03 May Shift 1)

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