A gardener pushes a lawn roller through a distance $20 \mathrm{~m}$. If he applies a force of $30…

A gardener pushes a lawn roller through a distance $20 \mathrm{~m}$. If he applies a force of $30 \mathrm{~kg}-\mathrm{wt}$ in a direction inclined at $60^{\circ}$ to the ground, the work done by the gardener in pushing the roller is
  1. $3640 \mathrm{~J}$
  2. $2460 \mathrm{~J}$
  3. $3940 \mathrm{~J}$
  4. $2940 \mathrm{~J}$

Solution

Consider the diagram below: $\begin{aligned} & \mathrm{W}=\mathrm{F} \Delta \mathrm{S} \cos (\theta) \\ & \mathrm{W}=\overrightarrow{\mathrm{F}} \cdot \overrightarrow{\Delta \mathrm{S}}=\mathrm{F} \Delta \mathrm{S} \cos 60^{\circ}=30 \times(9.8) 20 \times \frac{1}{2}=2940 \mathrm{~J}\end{aligned}$

Asked in: MHT CET 2022 (05 Aug Shift 2)

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