A galvanometer of resistance $100 \Omega$ requires $10 \mu$ A current for full scale deflection. Now a…
A galvanometer of resistance $100 \Omega$ requires $10 \mu$ A current for full scale deflection.
Now a resistance of $1 \Omega$ is connected to convert it into an ammeter. The minimum
current required to obtain full scale deflection is
$101 \mathrm{~mA}$
$1 \cdot 01 \mathrm{~mA}$
$11 \cdot 0 \mathrm{~mA}$
$10 \cdot 1 \mathrm{~mA}$
Solution
$\begin{aligned} I &=\left(\frac{G+S}{S}\right) I_{g} \\ &=\left(\frac{100+1}{1}\right) \times 10 \mu A \\ &=1010 \mu A=1.01 \mathrm{~mA} \end{aligned}$