A galvanometer having a coil resistance of $60 \Omega$ shows full scale deflection when a current of 1.0 A…

A galvanometer having a coil resistance of $60 \Omega$ shows full scale deflection when a current of 1.0 A passes through it. It can be converted into an ammeter to read currents upto $5.0 \mathrm{~A}$ by
  1. putting in parallel a resistance of $240 \Omega$
  2. putting in series a resistance of $15 \Omega$
  3. putting in series a resistance of $240 \Omega$
  4. putting in parallel a resistance of $15 \Omega$

Solution

Key Idea To convert a galvanometer to ammeter a small resistance is connected in parallel to the coil of the galvanometer. $\begin{aligned} & \text {Here, } \mathrm{G}_1=60 \Omega, \mathrm{I}_{\mathrm{g}}=1.0 \mathrm{~A}, \mathrm{I}=5 \mathrm{~A} \\ & \mathrm{I}_{\mathrm{g}} \mathrm{G}_1=\left(\mathrm{I}-\mathrm{I}_{\mathrm{g}}\right) \mathrm{S} \\ & \mathrm{S}=\frac{\mathrm{I}_{\mathrm{g}} \mathrm{G}_1}{\mathrm{I}-\mathrm{I}_{\mathrm{g}}}=\frac{1}{5-1} \times 60=15 \Omega \end{aligned}$ Putting $15 \Omega$ resistance in parallel.

Asked in: NEET 2009 (Screening)

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