A galvanometer has resistance ' $\mathrm{G}^{\prime}$ and range ${ }^{\prime} \mathrm{V}_{\mathrm{g}}{…
A galvanometer has resistance ' $\mathrm{G}^{\prime}$ and range ${ }^{\prime} \mathrm{V}_{\mathrm{g}}{ }^{\prime}$. How much resistance is required to
read voltage upto ' $\mathrm{V}$ ' volt?
$\frac{G\left(V+V_{g}\right)}{V}$
$G\left(\frac{V}{V_{g}}-1\right)$
$\frac{G\left(V-V_{g}\right)}{V}$
$\mathbf{G} \mathrm{V}_{\mathrm{g}}$
Solution
$\mathrm{G}(\mathrm{V} / \mathrm{Vg}-1)$ is required to read voltage upto V volt
/