A galvanometer has resistance $80 \Omega$ and it is shunted with resistance $20 \Omega$. If $20 \%$ of the…

A galvanometer has resistance $80 \Omega$ and it is shunted with resistance $20 \Omega$. If $20 \%$ of the main current flows through galvanometer, then what is the value of main current?
  1. 0.2 A
  2. 0.8 A
  3. 1 A
  4. 1.2 A

Solution


$\begin{aligned} & I=I_1+I_2 \\ & I_1=0.2 \mathrm{I} \quad \therefore \quad \mathrm{I}_2=0.8 \mathrm{I} \\ & \text { Also, } \mathrm{I}_1 \mathrm{G}=\mathrm{I}_2 \mathrm{~S} \\ \therefore \quad & 0.2 \mathrm{I} \times 80=0.8 \mathrm{I} \times 20 \\ \therefore \quad & \mathrm{I}=1 \mathrm{~A}\end{aligned}$

Asked in: MHT CET 2024 (15 May Shift 1)

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