A galvanometer coil has 500 turns and each turn has an average area of 3 × 10 - 4 m 2 . If a torque of…

A galvanometer coil has 500 turns and each turn has an average area of 3×10-4m2. If a torque of 1.5 Nm is required to keep this coil parallel to a magnetic field when a current of 0.5A is flowing through it, the strength of the field (in T) is _________ .

Solution

τ=M×B=NiAB sin90°

=NiAB=Ni S B

   B=τNiS=1.5500×0.5×3×10-4=20

Asked in: JEE Main 2020 (03 Sep Shift 2)

Practice more Current Electricity questions on Aicharya