A fully charged capacitor $C$ with initial charge $q_0$ is connected to a coil of self inductance $L$ at…

A fully charged capacitor $C$ with initial charge $q_0$ is connected to a coil of self inductance $L$ at $t=0$. The time at which the energy is stored equally between the electric and the magnetic field is :
  1. $\frac{\pi}{4} \sqrt{L C}$
  2. $2 \pi \sqrt{L C}$
  3. $\sqrt{L C}$
  4. $\pi \sqrt{L C}$

Solution

Charge oscillates simple harmonic motion $q=q_0 \sin \omega t, U=\frac{1}{2} \frac{q^2}{C}$ $ \begin{aligned} & q=\frac{q_0}{\sqrt{2}} \Rightarrow \omega t=\frac{\pi}{4} \\ & \Rightarrow t=\frac{T}{8}=\frac{2 \pi}{8} \sqrt{L C}=\frac{\pi}{4} \sqrt{L C} \end{aligned} $

Asked in: JEE Main 2011

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