A fully charged capacitor of capacity ' $\mathrm{C}$ ' is discharged through a small resistance wire…
- $\begin{aligned} & \left(\frac{\mathrm{ms} \Delta \mathrm{t}}{\mathrm{C}}\right)^2 \end{aligned}$
- $\begin{aligned}& \left(\frac{2 \mathrm{~ms} \Delta \mathrm{t}}{\mathrm{C}}\right)^{1 / 2} \end{aligned}$
- $\begin{aligned} &\frac{\mathrm{ms} \Delta \mathrm{t}}{\mathrm{C}}\end{aligned}$
- $\begin{aligned}& \frac{3 \mathrm{~ms} \Delta \mathrm{t}}{\mathrm{C}}\end{aligned}$
Solution
Asked in: AP EAMCET 2017 (26 Apr Shift 2)