A force of F = ( 5 y + 20 ) j ^   N acts on a particle. The work done by this force when the particle is moved from y = 0   m to y = 10   m is ________ J .

Question

A force of F = ( 5 y + 20 ) j ^ &#160; N acts on a particle. The work done by this force when the particle is moved from y = 0 &#160; m to y = 10 &#160; m is ________ J .

Aicharya · Accepted Answer

F = ( 5 y + 20 ) j ^ &#969; = &#8747; F d y = &#8747; 0 10 ( 5 y + 20 ) dy = 5 y 2 2 + 20 y 0 10 = 5 2 &#215; 100 + 20 &#215; 10 = 250 + 200 = 450 &#160; J

A force of F = ( 5 y + 20 ) j ^   N acts on a particle. The work done by this force when the particle…

Solution

A force of F = ( 5 y + 20 ) j ^ &#160; N acts on a particle. The work done by this force when the particle…

Solution

A force of F = ( 5 y + 20 ) j ^ N acts on a particle. The work done by this force when the particle…