A force is represented by F = a x 2 + b t 1 2 , where x = distance and t = time. The dimensions of b 2 a are :

A force is represented by F=ax2+bt12, where x= distance and t= time. The dimensions of b2a are :
  1. [ML3 T 3]
  2. [MLT2]
  3. [ML1 T1]
  4. [ML2 T3]

Solution

Given: F=ax2+bt12

Dimension of a=Fx2=MLT-2L2=M1L-1T-2

Dimension of b=Ft12=MLT-2T12=M1L1T-52

Required value, b2a=M2L2T-5M1L-1T-2=M1L3T-3

Asked in: JEE Main 2024 (31 Jan Shift 1)

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