A force $\overrightarrow{\mathrm{F}}=2 \hat{i}+\mathrm{b} \hat{j}+\hat{k}$ is applied on a particle and it…

A force $\overrightarrow{\mathrm{F}}=2 \hat{i}+\mathrm{b} \hat{j}+\hat{k}$ is applied on a particle and it undergoes a displacement $\hat{i}-2 \hat{j}-\hat{k}$. What will be the value of $b$, if work done on the particle is zero.
  1. 0
  2. $\frac{1}{2}$
  3. 2
  4. $\frac{1}{3}$

Solution

$\begin{aligned} & w=0 \\ & \therefore \quad \vec{F} \cdot S=0 \\ & (2 \hat{i}+b \hat{j}+\hat{k}) \cdot(\hat{i}-2 \hat{j}-\hat{k})=0 \\ & 2-2 b-1=0 \\ & b=\frac{1}{2}\end{aligned}$

Asked in: JEE Main 2025 (22 Jan Shift 2)

Practice more Work Power Energy questions on Aicharya