A force F → = 2 + 3 x i ^ acts on a particle in the x direction where F is in Newton and x is in meter…

A force F=2+3xi^ acts on a particle in the x direction where F is in Newton and x is in meter. The work done by this force during a displacement from x = 0 to x=4 m is _____ J.

Solution

The formula to calculate the work done by a variable force is given by

W=x1x2Fdx   ...1

Substitute the values of the known parameters into equation (1) to calculate the required work done.

W=04(2+3x)dx=2x+32x204=[8+24] J=32 J

Asked in: JEE Main 2023 (11 Apr Shift 1)

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