A force F = 20 + 10 y acts on a particle in y -direction where F is in Newton and y is in meter. Work done…

A force F=20+10y acts on a particle in y-direction where F is in Newton and y is in meter. Work done by this force to move the particle from y=0 to y=1 m is
  1. 30 J
  2. 5 J
  3. 25 J
  4. 20 J

Solution

Work done is calculated by taking the dot product between the force and the displacement.

W=∫F·dy
=∫0120 dy+∫0110 y dy
=20 y01+5y201
=20+5=25 J

Asked in: NEET 2019 (All India)

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