\(A\) force \(\mathbf{F}=(5 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{N}\) acts on a body and produces a…

\(A\) force \(\mathbf{F}=(5 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{N}\) acts on a body and produces a displacement \(s=(6 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}) \mathrm{m}\). The work done by the force is
  1. \(10 \mathrm{~J}\)
  2. \(20 \mathrm{~J}\)
  3. \(30 \mathrm{~J}\)
  4. \(40 \mathrm{~J}\)

Solution

Force applied on the body, \(\begin{aligned} \mathbf{F} & =(5 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{N} \\ \text {Displacement, } \mathbf{s} & =(6 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}) \mathrm{m} \\ \therefore \text { Work done, } W & =\mathbf{F} \cdot \mathbf{s}=(5 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \cdot(6 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}) \\ & =30-20+0=10 \mathrm{~J} \end{aligned}\)

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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