A fly wheel rotating about a fixed axis has a kinetic energy of 360 joule when its angular speed is 30…
- $0.6 \mathrm{~kg} / \mathrm{m}^{2}$
- $0.15 \mathrm{~kg} \mathrm{~m}^{2}$
- $0.8 \mathrm{~kg} \mathrm{~m}^{2}$
- $0.75 \mathrm{~kg} \mathrm{~m}^{2}$
Solution
$I=\frac{2 E_{r}}{\omega^{2}}=\frac{2 \times 360}{30 \times 30}=0.8 \mathrm{~kg} \mathrm{~m}^{2}$ ^
Asked in: JEE Mains - Rotational Motion - Test 2