A fluid of density ' $\rho$ ' is flowing through a uniform tube of diameter ' $\mathrm{d}$ '. The…
A fluid of density ' $\rho$ ' is flowing through a uniform tube of diameter ' $\mathrm{d}$ '. The coefficient of viscosity of the fluid is ' $\eta$ ', then critical velocity of the fluid is
inversely proportional to ' $\eta$ '
directly proportional to ' $\eta$ '
directly proportional to 'd'
directly proportional to ' $\rho$ '
Solution
The equation for critical velocity is given as:
$\mathrm{v}=\mathrm{k} \frac{\eta}{\rho \mathrm{r}}$
$\therefore \quad$ The critical velocity is directly proportional to $\eta$.
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