A fission reaction is given by U 92 236 → X e 54 140 + S r 38 94 + x + y , where x and y are two particles. Considering U 92 236 to be at rest, the kinetic energies of the products are denoted by K X e ,   K S r ,   K x ( 2   M e V ) and K y 2   M e V , respectively. Let…

Question

A fission reaction is given by U 92 236 &#8594; X e 54 140 + S r 38 94 + x + y , where x and y are two particles. Considering U 92 236 to be at rest, the kinetic energies of the products are denoted by K X e , &#160; K S r , &#160; K x ( 2 &#160; M e V ) and K y 2 &#160; M e V , respectively. Let the binding energies per nucleon of U 92 236 , &#160; X e 54 140 &#160; and S r 38 94 be 7.5 MeV, 8.5 MeV, and 8.5 MeV respectively. Considering different conservation laws, the correct option(s) is (are)

Aicharya · Accepted Answer

U → X e + S r + x + 2 y 2 Q = 4 + K X e + K S r ...(i) - Q = E B = 236 × 7.5 - 140 × 8.5 - 94 × 8.5 ∴ Q = 219 ...(ii) ∴ K X e + K S r = 215 M e V Since, both x & y have same KE ∴ both particles should have same mass & lighter body will have higher KE. .

A fission reaction is given by U 92 236 → X e 54 140 + S r 38 94 + x + y , where x and y are two…

Solution

A fission reaction is given by U 92 236 &#8594; X e 54 140 + S r 38 94 + x + y , where x and y are two…

Solution

A fission reaction is given by U 92 236 → X e 54 140 + S r 38 94 + x + y , where x and y are two…