A first order reaction is half-completed in 45 minutes. How long does it need for $99.9 \%$ of the reaction…
- 20 hours
- 10 hours
- $7 \frac{1}{2}$ hours
- 5 hours
Solution
$t=\frac{2.303}{0.693} \times 45 \log \frac{100}{100-99.9}$
$=\frac{2.303 \times 45 \times 3}{0.693}=7 \frac{1}{2}$ hours.
Asked in: JEE-TOPICTESTS-CHEMISTRY