A Diwali cracker releases 25 gram gas per second, with a speed of $400 \mathrm{~ms}^{-1}$ after explosion.…
A Diwali cracker releases 25 gram gas per second, with a speed of $400 \mathrm{~ms}^{-1}$ after
explosion. The force exerted by gas on the cracker is
- 100 dyne
- 16 newton
- 10 newton
- 10,000 dyne
Solution
$\mathrm{F}=$ rate of change of momentum
$=25 \times 10^{-3} \mathrm{~kg} / \mathrm{s} \times 400 \mathrm{~m} / \mathrm{s}$ $=10 \mathrm{~N}$
Asked in: MHT CET 2020 (13 Oct Shift 2)
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