A disc of moment of inertia \(I_1\) is rotating with an angular velocity \(\omega_1\). Another disc of…

A disc of moment of inertia \(I_1\) is rotating with an angular velocity \(\omega_1\). Another disc of moment of inertia \(I_2\) which is not rotating, is gently put on the first disc. The angular speed of the system will be
  1. \(\left(\frac{l_1+I_2}{l_1}\right) \omega_1\)
  2. \(\left(\frac{I_1}{I_1+I_2}\right) \omega_1\)
  3. \(\left(\frac{l_1-I_2}{l_1}\right) \omega_1\)
  4. \(\left(\frac{I_1}{I_1-I_2}\right) \omega_1\)

Solution

Since, no external torque acts on the system, hence by the law of conservation of angular momentum, \(\begin{aligned} & I_1 \omega_1=\left(I_1+I_2\right) \omega_2 \\ & {\left[\omega_2=\text { final angular velocity of system }\right] } \\ \Rightarrow \quad & \omega_2=\left(\frac{I_1}{I_1+I_2}\right) \omega_1 \end{aligned}\)

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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