A disc is rolling without slipping on a surface. The radius of the disc is $R .$ At $t = 0,$ the top most point on the disc is $A$ as shown in figure. When the disc completes half of its rotation, the displacement of point $A$ from its initial position is

Question

Aicharya · Accepted Answer

The displacement is the hypotenuse of the diameter and the distance travelled for half the rotation $π R$ .
By using Pythagoras theorem,
Displacement of $A = \sqrt{(2 R)^{2} + (π R)^{2}}$
$= R \sqrt{π^{2} + 4}$

A disc is rolling without slipping on a surface. The radius of the disc is R . At t = 0 , the top most point…

Solution