A dilute solution of sulphuric acid is electrolysed using a current of 0 . 10   A for 2 hours to…

At anode

$2{\mathrm{H}}_2\mathrm{O}\to {\mathrm{O}}_2\left(\mathrm{g}\right)+4{\mathrm{H}}^{+}+4{\mathrm{e}}^{-}$

At cathode

$2{\mathrm{H}}^{+}+2{\mathrm{e}}^{-}\to {\mathrm{H}}_2\left(\mathrm{g}\right)$

Now number of gm eq. $=\frac{\mathrm{i}\times \mathrm{t}}{96500}$

$=\frac{0.1\times 2\times 60\times 60}{96500}$

$=0.00746$

${\mathrm{V}}_{{\mathrm{O}}_2}=\frac{0.00746}{4}\times 22.7=0.0423$

${\mathrm{V}}_{{\mathrm{H}}_2}=\frac{0.00746}{2}\times 22.7=0.0846$

${\mathrm{V}}_{\mathrm{Total}}\approx 127\mathrm{ml}$ or $\mathrm{cc}$