A dielectric slab of thickness \(d\) is inserted in a parallel plate capacitor whose negative plate is at…
A dielectric slab of thickness \(d\) is inserted in a parallel plate capacitor whose negative plate is at \(x=0\) and positive plate is at \(x=3 d\). The slab is equidistant from the plates. The capacitor is given some charge. As \(x\) goes from 0 to \(3 d\),
the magnitude of the electric field remains the same
the direction of the electric field changes continuously
the electric potential increases continuously
the electric potential increases at first, then decreases and again increases.
Solution
The insertion of the dielectric slab decreases the electric field without changing its direction. The electric potential increases as we go from the negative to the positive plate. Hence the correct choice is (c).