A die is thrown $(2 n+1)$ times. The probability of getting 1 or 3 or 4 atmost $n$ times on it is

A die is thrown $(2 n+1)$ times. The probability of getting 1 or 3 or 4 atmost $n$ times on it is
  1. $\frac{1}{n}$
  2. $\frac{1}{2 n+1}$
  3. $\frac{n}{2 n+4}$
  4. $\frac{1}{2}$

Solution

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Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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