A die is thrown. Let $A$ be the event that the number obtained is greater than 3 . Let $B$ be the event that…

A die is thrown. Let $A$ be the event that the number obtained is greater than 3 . Let $B$ be the event that the number obtained is less than 5 . Then $P(A \cup B)$ is
  1. $\frac{3}{5}$
  2. 0
  3. 1
  4. $\frac{2}{5}$

Solution

$ A=\{4,5,6\}, B=\{1,2,3,4\} \text {. } $ Obviously $P(A \cup B)=1$

Asked in: JEE Main 2008

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