A die is thrown five times. If getting an odd number is a success, then the probability of getting at least 4 successes is

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Aicharya · Accepted Answer

Here, $n=5, p=\frac{1}{2}, q=\frac{1}{2}$ Probability of getting at least 4 successes $\begin{aligned} & \mathrm{P}(\mathrm{x}=4 	ext { or } \mathrm{x}=5)={ }^5 \mathrm{C}_4\left(\frac{1}{2}ight)^4\left(\frac{1}{2}ight)^1+{ }^5 \mathrm{C}_5\left(\frac{1}{2}ight)^5\left(\frac{1}{2}ight)^{\circ} \ & =5 	imes \frac{1}{16} 	imes \frac{1}{2}+1 	imes \frac{1}{32} 	imes 1 \ & =\frac{5}{32}+\frac{1}{32} \ & =\frac{6}{32}=\frac{3}{16}\end{aligned}$

A die is thrown five times. If getting an odd number is a success, then the probability of getting at least…

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