A die is rolled. Probability of NOT getting a $6$ is:

A die is rolled. Probability of NOT getting a $6$ is:
  1. $\dfrac{1}{6}$
  2. $\dfrac{2}{3}$
  3. $\dfrac{5}{6}$
  4. $\dfrac{6}{5}$

Solution

$P(6) = \dfrac{1}{6}$, so $P(\text{not }6) = 1 - \dfrac{1}{6} = \dfrac{5}{6}$.

Asked in: IMO

Practice more DATA HANDLING questions on Aicharya