A die is rolled. Probability of getting an even number OR a number greater than $4$ is:
A die is rolled. Probability of getting an even number OR a number greater than $4$ is:
- $\dfrac{1}{2}$
- $\dfrac{2}{3}$
- $\dfrac{5}{6}$
- $\dfrac{1}{3}$
Solution
Even $= \{2,4,6\}$, $>4 = \{5,6\}$. Union $= \{2,4,5,6\}$. $P = \dfrac{4}{6} = \dfrac{2}{3}$.
Asked in: IMO
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