A die is rolled. Probability of getting a number that is even OR a multiple of $3$ is:

A die is rolled. Probability of getting a number that is even OR a multiple of $3$ is:
  1. $\dfrac{1}{2}$
  2. $\dfrac{2}{3}$
  3. $\dfrac{5}{6}$
  4. $\dfrac{1}{3}$

Solution

Even $= \{2,4,6\}$, multiples of $3 = \{3,6\}$. Union $= \{2,3,4,6\}$. $P = \dfrac{4}{6} = \dfrac{2}{3}$.

Asked in: IMO

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