A diatomic ideal gas is used in Carnot's engine as working substance. During adiabatic expansion of the…
- 0.25
- 0.5
- 0.67
- 0.75
Solution

Given, volume at $C=V$ and volume at $D=32 \mathrm{~V}$ For adiabatic expansion $C D$, $ \begin{aligned} T_C V_C^{\gamma-1} & =T_D V_D^{\gamma-1} \Rightarrow \frac{T_C}{T_D}=\left(\frac{V_D}{V_C}\right)^{\gamma-1} \\ & =\left(\frac{32 V}{V}\right)^{\gamma-1}=32^{\frac{7}{5}-1} \\ \Rightarrow \quad \frac{T_C}{T_D} & =(32)^{\frac{2}{5}}=4 \end{aligned} $ Now, efficiency of Carnot's cycle, $ \eta=1-\frac{T_D}{T_C}=1-\frac{1}{4}=\frac{3}{4}=0 \cdot 75 $
Asked in: AP EAMCET 2018 (22 Apr Shift 2)