A diatomic gas undergoes adiabatic change. Its pressure P and temperature T are related as $\mathrm{P}…
- $3.5$
- $2.5$
- $4.5$
- 3
Solution
For diatomic gas, $\begin{array}{ll} & \gamma=\frac{7}{5} \\ \therefore \quad & \frac{1-\gamma}{\gamma}=-\frac{2}{7} \\ & \mathrm{TP}^{-2 / 7}=\text { constant } \\ & \Rightarrow \mathrm{P} \propto \mathrm{~T}^{7 / 2} \Rightarrow \mathrm{P} \propto \mathrm{~T}^{3.5} \\ \therefore \quad & x=3.5 \end{array}$ .
Asked in: MHT CET 2024 (03 May Shift 2)