A cylindrical tube, with its base as shown in the figure., is filled with water. It is moving down with a…

A cylindrical tube, with its base as shown in the figure., is filled with water. It is moving down with a constant acceleration a along a fixed inclined plane with angle θ=45°P1 and P2 are pressures at point 1 and 2, respectively, located at the base of the tube. Let β=P1P2ρgd, where ρ is density of water, d is the inner diameter of the tube and g is the acceleration due to gravity. Which of the following statement(s) is (are) correct?

  1. β=0 when a=g2
  2. β>0 when a=g2
  3. β=2-12 when a=g2
  4. β=12 when a=g2

Solution

Given,

β=P1P2ρgd       ...1

Here we can write now,

P3=P2+ρga2d

P1=P3ρa2d

P1=P2+ρgd2ρad

P1=P2+ρga2dρa2d

P1P2ρdg=12ag

Compare it with given equation 1,

β=12ag

Now check the options,

If a=g2β=0.

If a=g2β=2-12.

Option 1and 3 are correct

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Asked in: JEE Advanced 2021 (Paper 1)

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