A cylindrical container has diameter $14$ cm and height $10$ cm. Its volume is (use $\pi=\dfrac{22}{7}$):
A cylindrical container has diameter $14$ cm and height $10$ cm. Its volume is (use $\pi=\dfrac{22}{7}$):
- $1540 \text{ cm}^{3}$
- $770 \text{ cm}^{3}$
- $3080 \text{ cm}^{3}$
- $616 \text{ cm}^{3}$
Solution
$r = 7, h = 10$. $V = \pi r^{2} h = \dfrac{22}{7} \times 49 \times 10 = 1540 \text{ cm}^{3}$.
Asked in: IMO
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