A cylinder has volume $4400 \text{ cm}^{3}$ and height $14$ cm. Its radius is (use $\pi=\dfrac{22}{7}$):
A cylinder has volume $4400 \text{ cm}^{3}$ and height $14$ cm. Its radius is (use $\pi=\dfrac{22}{7}$):
- $5$ cm
- $10$ cm
- $7$ cm
- $14$ cm
Solution
$\pi r^{2} h = 4400 \Rightarrow \dfrac{22}{7} \times r^{2} \times 14 = 4400 \Rightarrow 44 r^{2} = 4400 \Rightarrow r^{2} = 100 \Rightarrow r = 10$ cm.
Asked in: IMO
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