
A cylinder contains water upto a height 'H'. It has three orifices $\mathrm{O}_1, \mathrm{O}_2,…

- $\mathrm{V}_1=\mathrm{V}_2=\mathrm{V}_3$
- $V_1 \lt V_2 \lt V_3$
- $\mathrm{V}_1\gt\mathrm{V}_2\gt\mathrm{V}_3$
- $\quad \mathrm{V}_1=\mathrm{V}_3\gt\mathrm{V}_2$
Solution

We know, $V=\sqrt{2 g h}$ ...(where ' $h$ ' is depth from the surface) ...(From figure) $\begin{array}{ll} & \mathrm{h}_1 \lt \mathrm{h}_2 \lt \mathrm{h}_3 \\ \therefore \quad & \mathrm{~V}_1 \lt \mathrm{V}_2 \lt \mathrm{V}_3\end{array}$
Asked in: MHT CET 2024 (16 May Shift 1)
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