
A cyclist starts from the point $P$ of a circular ground of radius $2 \mathrm{~km}$ and travels along its…

- $\sqrt{8} \mathrm{~km}$
- $8 \mathrm{~km}$
- $6 \mathrm{~km}$
- $4 \mathrm{~km}$
Solution

$\therefore$ Displacement $=\mathrm{R} \sqrt{2}=2 \sqrt{2}=\sqrt{8} \mathrm{~km}$
Asked in: JEE Main 2024 (04 Apr Shift 2)