A current ' $I$ ' produces a magnetic flux ' $\phi$ ' per turn in a coil of ' $n$ ' turns. Self-inductance…

A current ' $I$ ' produces a magnetic flux ' $\phi$ ' per turn in a coil of ' $n$ ' turns. Self-inductance of the coil is ' $L$ '. The relation between them is
  1. $\mathrm{nLI}=\phi$
  2. $\frac{\mathrm{nL}}{\mathrm{I}}=\phi$
  3. $\frac{\mathrm{LI}}{\mathrm{n}^2}=\phi$
  4. $\frac{\mathrm{LI}}{\mathrm{n}}=\phi$

Solution

$\begin{aligned} & \mathrm{n} \phi=\mathrm{LI} \\ & \therefore \frac{\mathrm{LI}}{\mathrm{n}}=\phi\end{aligned}$

Asked in: MHT CET 2021 (24 Sep Shift 2)

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