A current of $2 \mathrm{~A}$ flows in an electric circuit as shown in figure. The potential difference…

A current of $2 \mathrm{~A}$ flows in an electric circuit as shown in figure. The potential difference $\left(V_R-V_S\right)$, in volts $\left(V_R\right.$ and $V_S$ are potentials at $R$ and $S$ respectively) is
  1. $-4$
  2. $+2$
  3. $+4$
  4. $-2$

Solution

Current through each arm $ \begin{gathered} P R Q \text { and } P S Q=1 \mathrm{~A} \\ V_P-V_R=3 \mathrm{~V} \\ V_P-V_S=7 \mathrm{~V} \end{gathered} $ From Eqs. (i) and (ii), we get $ V_R-V_S=+4 \mathrm{~V} $

Asked in: AP EAMCET 2008

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