A current of 6   A enters one corner P of an equilateral triangle P Q R having 3 wires of resistance 2…

A current of 6 A enters one corner P of an equilateral triangle PQR having 3 wires of resistance 2 Ω each and leaves by the corner R. The currents i1 in ampere is

Solution

For parallel combination, current divides in the inverse ratio of resistance.

iPQ=26×6 A=2 A.

Asked in: JEE Main 2021 (25 Feb Shift 2)

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