A current of 10 . 0   A flows for 2 . 00   h through an electrolytic cell containing a molten salt…

Quantity of Electricity $=\frac{10\times 3600\times 2}{96500}$
                                   $=0.746\approx 0.75\mathrm{F}$.
If oxidation state is ${\mathrm{n}}^{+}$ for $1 \mathrm{mol}$ deposition of a metal:
Electricity$=\mathrm{nF}$ (Faradays)
For $0.250 \mathrm{mol}$$=0.250 nF$
$\therefore 0.250 nF=0.75 F$
$\mathrm{n}=3$