
A current \(I\) a flows in a circular arc of radius \(r\) subtending an angle \(\theta\) as shown in the…

- \(\frac{\mu_0 I \theta}{4 \pi r}\)
- \(\frac{2 \mu_0 I \cdot \sin \theta}{4 \pi r}\)
- \(\frac{2 \mu_0 I \sin \theta}{2 r}\)
- \(\frac{2 \mu_0 I \sin \theta}{4 r}\)
Solution

Magnetic field due to current carrying circular arc making an angle \(\theta\) at the centre, is given as \(\begin{aligned} & B=\frac{\theta}{2 \pi} \cdot B_C=\frac{\theta}{2 \pi} \cdot \frac{\mu_0 I}{2 r} \text { [From Eq. (i)] } \\ & B=\frac{\mu_0 I \theta}{4 \pi r} \end{aligned}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 1)
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