A current $\mathrm{I}=10 \sin (100 \pi \mathrm{t})$ ampere, is passed in coil which induces a maximum emf $5…
A current $\mathrm{I}=10 \sin (100 \pi \mathrm{t})$ ampere, is passed in coil which induces a maximum emf $5 \pi$ volt in neighboring coil. The mutual inductance of two coils is
5mH
10mH
15mH
25mH
Solution
Induced emf $\mathrm{e}=\mathrm{M} \frac{\mathrm{dI}}{\mathrm{dt}}=\mathrm{M} \times 1000 \pi \cos (100 \pi \mathrm{t})$
The maximum value of emf, $\mathrm{e}_0=1000 \pi \mathrm{M}$
$\therefore \mathrm{M}=\frac{5 \pi}{1000 \pi}=5 \mathrm{mH}$