A cuboidal room is $8$ m long, $6$ m wide and $5$ m high. Find the area of its four walls.
A cuboidal room is $8$ m long, $6$ m wide and $5$ m high. Find the area of its four walls.
- $140 \text{ m}^{2}$
- $240 \text{ m}^{2}$
- $120 \text{ m}^{2}$
- $70 \text{ m}^{2}$
Solution
Area of four walls $= 2 h (l+b) = 2 \times 5 \times (8+6) = 10 \times 14 = 140 \text{ m}^{2}$.
Asked in: IMO
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