A cubic lattice has atoms of $A$ at the body centre, atoms of $B$ at the corners of the cube and atoms $C$…
A cubic lattice has atoms of $A$ at the body centre, atoms of $B$ at the corners of the cube and atoms $C$ at all the face centres. What is its formula?
$A B C_3$
$A B C_2$
$A B_2 \mathrm{C}$
$A_2 B C_3$
Solution
Number of atoms of $A=1$ ( 1 atom is present at centre of cell)
Number of atoms of $B=$ Number of corners
$\times$ Contribution of each atom
$
=8 \times \frac{1}{8}=1
$
Number of atoms of $C=$ Number of faces
$\times$ Contribution of each atom
$
=6 \times \frac{1}{2}=3
$
Therefore, formula of compound $=A B C_3$