A cricket ball of mass 0 . 15   kg is thrown vertically up by a bowling machine so that it rises to a…

A cricket ball of mass 0.15 kg is thrown vertically up by a bowling machine so that it rises to a maximum height of 20 m after leaving the machine. If the part pushing the ball applies a constant force F on the ball applies a constant force F on the ball and moves horizontally a distance of 0.2 m while launching the ball, the value of F(in N) is g=10 m s-2

Solution

From work energy theorem F0.2-mg20=0

F=mg200.2

=mg2002

=0.15×10×2002

=150.00 N

Asked in: JEE Main 2020 (03 Sep Shift 1)

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