A convex lens of focal length 'F' produces a real image 'n' times the size of the object. The image distance…
A convex lens of focal length 'F' produces a real image 'n' times the size of the
object. The image distance is
- $\mathrm{F}(\mathrm{n}+1)$
- $\mathrm{F}(\mathrm{n}-1)$
- $\frac{\mathrm{F}}{(\mathrm{n}+1)}$
- $\frac{\mathrm{F}}{(\mathrm{n}-1)}$
Solution
$\frac{v}{u}=(-n) \quad \therefore v=(-u n)$
$\therefore \quad \frac{1}{F}=\frac{1}{v}-\frac{1}{u}$
$\frac{v}{F}=1-\frac{v}{u}=1+n$
$\therefore v=F(1+n)$
Asked in: MHT CET 2020 (15 Oct Shift 1)
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