A convex lens of focal length 30 cm is placed in contact with a concave lens of focal length 20 cm. An…
- 30
- 45
- $\frac{60}{7}$
- 15
Solution
$\begin{aligned}
& \frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2} \\ & =\frac{1}{30}+\frac{1}{-20}=\frac{2-3}{60}=-\frac{1}{60} \\ & f=-60 \mathrm{~cm}
\end{aligned}$
Lens formula
$\begin{aligned}
& \frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}} \\ & \frac{1}{\mathrm{v}}-\frac{1}{-20}=\frac{1}{-60} \\ & \mathrm{v}=-15 \mathrm{~cm}
\end{aligned}$
Asked in: JEE Main 2025 (08 Apr Shift 2)