A constant voltage of $25 \mathrm{~V}$ is applied to a series $L-R$ circuit at $t=0$, by closing a switch.…
- $0 \mathrm{~V}, 25 \mathrm{~V}$
- $12.5 \mathrm{~V}, 1.25 \mathrm{~V}$
- $10 \mathrm{~V}, 15 \mathrm{~V}$
- $25 \mathrm{~V}, 0 \mathrm{~V}$
Solution

Current $i=i_0\left[1-e^{-t R / L}\right]$ So, at $t=0, i=0$ So, potential across inductor $=25 \mathrm{~V}$ and across resistor $=0 \mathrm{~V}$
Asked in: AP EAMCET 2011