A constant torque of $100 \mathrm{~N} \mathrm{~m}$ turns a wheel of moment of inertia $300 \mathrm{~kg} \mathrm{~m}^2$ about an axis passing through its centre. Starting from rest, its angular velocity after $3 \mathrm{~s}$ is

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Aicharya · Accepted Answer

About fixed axis $ightarrow$ Torque $=I \alpha$ $\begin{aligned} & \alpha=\frac{100}{300} \ & \alpha=\frac{1}{3} \mathrm{rad} / \mathrm{s}^2\end{aligned}$ $\begin{aligned} & \Rightarrow \omega_i=0 \ & \omega_f=\omega_i+\alpha t \ & 	ext { at } t=3 \mathrm{~s} \ & \omega_f=\frac{1}{3} 	imes 3=1 \mathrm{rad} / \mathrm{s}\end{aligned}$

A constant torque of $100 \mathrm{~N} \mathrm{~m}$ turns a wheel of moment of inertia $300 \mathrm{~kg}…

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